DJ type large inclination sidewall belt conveyor - Lift Conveyor Equipment - Shandong Kehua Heavy Industry Technology Co., Ltd.

DJ type large inclination sidewall belt conveyor

１ Overview　　This series of products is mainly used for the continuous conveying of bulk materials at large in

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１. Overview

　　This series of products is mainly used for the continuous conveying of bulk materials at large inclination angles, and adopts conveyor belts with corrugated sidewalls and transverse partitions. The conveying inclination angle is 0-90° (70° is the best), and its characteristics are: the horizontal inclined conveying can be completed in a narrow space with one equipment, and it has a general belt conveyor with high reliability, energy saving and low inclination conveying. Bucket elevators have the advantages of reliable and economical lifting of materials. This series of products are widely used in coal, grain, building materials, chemical industry, hydropower and metallurgy and other departments to transport various bulk materials with a bulk density of 0.5-2.5t/m3 in the ambient temperature range of -19℃-+40℃. For materials with special requirements for conveying, such as materials with high temperature resistance or ingredients such as acid, alkali, oily substances, organic solvents, etc., it must be proposed when ordering, and special sidewall conveyor belts of corresponding materials should be used.

2. Technical parameters:

带宽B		400		500		600		800		1000		1200		1400
挡边高H		60	80	80	120	120	160	160	200	160	240	200	600	240	400
最小横隔板间距		100	120	120	160	160	200	200	250	200	280	250	350	280	400
输送量（原煤、带速1m/s）M 3/h	35°	28	36	50	71	104	120	157	195	216	327	331	466	500	794
	45°	19	25	33	57	83	97	127	157	175	271	267	384	414	680
	60°	15	19	23	40	58	59	90	112	124	197	190	278	302	524
	90°	9	11	15	21	31	37	48	60	66	106	102	149	162	281
外型尺寸	头轮带面高H1	1200		1350		1615		1815		2000，2200		2300，2525		2525，2700
	尾轮带面高H2	690		800		950		1115		1250，1400		1600，1700		1600，1700
	中间段带面高H3	700		800		850		1115		850，1200		1400，1500		1600，1700
	中间段地脚宽B1	580		850		1020		1220		1440		1690		1890

Note: The conveying capacity in this product is calculated according to the minimum spacing between the diaphragms, the belt speed increases or decreases, and the conveying capacity increases or decreases exponentially; other materials can be determined by referring to this table.

粒度mm			《100	《160	《250mm
速度m/s	挡边高《120mm	倾角《30°	2	1.6
	挡边高《120mm	倾角《60°	1.6	1.25
	挡边高《240mm	倾角《30°	2.5	2	1.6
	挡边高《240mm	倾角《60°	1.6	1.6	1.0

3. Appearance drawing

4. Selection

　　According to the characteristics of the conveyed material, the inclination angle and the conveying volume, refer to Table 1 and Table 2 to determine the belt width, sidewall height and belt speed of the conveyor. in:

　　(1) The sidewall conveyor belt is divided into room temperature (-20～50℃), heat resistance (below 120℃), high temperature resistance (below 180℃), acid resistance, alkali resistance, oil resistance, etc.;

　　(2) When conveying bulk materials, the sidewall should be high; it is also possible to increase the conveying capacity by increasing the belt speed (1.25m/s, 1.6m/s, 2m/s) without increasing the bandwidth and sidewall. ;

　　(3) The maximum conveying height is 70m, and the maximum particle size should be 30-40mm less than the height of the rib.

　　(4) The distance between the upper rollers is generally 1.2m, the distance between the lower rollers is generally 1.2m, when the inclination angle is greater than 60°, it is 2.4m, and the distance between the anti-deviation rollers is 3-6m. L3 standard is 2200, minimum 1500.

　　(5) The power estimation is as follows.

　　Concise selection calculation table of large inclination belt conveyor

带宽 B（mm）	挡边高 H（mm）	30°		40°		60°		75°
带宽 B（mm）	挡边高 H（mm）	输送量 (m 3/h）	功率（Kw）	输送量 (m 3/h）	功率（Kw）	输送量 (m 3/h）	功率（Kw）	输送量 (m 3/h）	功率（Kw）
500	120	52.8	2.85	63.2	1.86	26.6	1.32	19.8	0.98
650	120	77.6	3.97	55.3	2.6	39	1.85	29	1.35
650	160	105	5.44	76.3	3.57	56.2	2.56	41.6	1.86
800	160	133	6.99	96.6	4.59	71.2	3.28	52.6	2.38
800	200	195	9.8	159.8	7.07	117.6	5.07	86.5	3.66

Instructions for use:

1. This table is only suitable for preliminary and simple selection, and the final selection result should be determined according to the calculation results.

2. The data in this table are calculated according to the tape linear velocity V=1m/s, the distance between the diaphragms ts=0.25m, the material is the capacity γ=1t/m3, and the lifting height H=10m is calculated under the assumptions, if the conditions are different, it should be appropriate Convert.

3. Selection example:

Known: the conveying material is coal, the capacity is γ=0.8t/m3, the material particle size is A<40mm, the conveying inclination is β=45°, the conveying volume Q=85t/h, the conveying height is 15m, find the required bandwidth and belt speed and motor power. First find that the conveying capacity of the belt conveyor should be 85t/h÷0.5t/m3,=106.25m3/h, and then find the conveying capacity of B=800 and H=160 in the 45° inclination column in the table 96.6m3/ h is the closest, and then change the line speed to 1.25m/s, then the conveying capacity of the tape becomes 96.6m 3/h×1.25=120.75m 3/h, which can meet the usage requirements. The corresponding required power is 4.59Kw×15m÷10m×1.25=8.6kw.

4. The form of the diaphragm is selected according to the inclination of the conveyor;

18°<β≤40°T type, 40°<β≤60°C type, 60°<β≤90° TC type

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